Math, asked by rdneelambari, 1 month ago

Answer the following find the area of the given triangle​

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Answered by suraj5070
56

 \sf \bf \huge {\boxed {\mathbb {QUESTION}}}

 \tt Find\: the\: area\: of \:the\: triangle.

 \sf \bf \huge {\boxed {\mathbb {ANSWER}}}

 \sf \bf {\boxed {\mathbb {GIVEN}}}

  •  \bf Base\:of\: the \:triangle(b) = 6.4\:cm
  •  \bf Height \:of\: the \:triangle(h) = 6\:cm

 \sf \bf {\boxed {\mathbb {TO\:FIND}}}

  •  \bf Area\:of\: the \:triangle

 \sf \bf {\boxed {\mathbb {SOLUTION}}}

 {\pink {\underline {\pmb {\bf {Area\: of\: the\: triangle}}}}}

 {\blue {\boxed {\boxed {\boxed {\green {\pmb {A_{(Triangle)}=\dfrac{1}{2}bh}}}}}}}

  •  \sf A=area \:of\: the\: triangle
  •  \sf b=base \:of\: the\: triangle
  •  \sf h=height\:of\: the\: triangle

 {\underbrace {\overbrace {\orange {\pmb {Substitute \:the \:values}}}}}

 \bf \implies A=\dfrac{1}{2}\times 6.4\times 6

 \bf \implies A=\dfrac{1}{\cancel{2}}\times 6.4\times \cancel{6}

 \bf \implies A=6.4\times 3

 \implies{\blue {\boxed {\boxed {\purple {\mathfrak {A=19.2\:{cm}^{2}}}}}}}

 {\underbrace {\red {\underline {\red {\overline {\red {\pmb {\sf {{\therefore} The\:area\: of \:the\: triangle\: is \:19.2\:{cm}^{2}}}}}}}}}}

_____________________________________________

 \sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}

 \sf Area \:of \:the\:triangle =\dfrac{1}{2}bh

 \sf Perimeter\:of \:the\:triangle =a+b+c

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