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Answer the following:


→if (-1,1) is a solution of 6x+5y-k = 0 then write any two solutions of kx+3y-8=0

→if (2,-1) is a solution of 4x+by+4=0 and ax-2y+3=0 then find value of a+b

→write 3 points passes through which the graph of x=y passes

→the line ax+by+c=0 meets y axis at which point

→the line ax+by+c=0 meets X axis at which point

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Answered by assingh
37

Concept Used :-

If any point is solution of any line then it must satisfy the equation of line.

If any line meet at X - axis, then Y - coordinate of point intersecting X - axis is zero.

If any line meet at Y - axis, then X - coordinate of point intersecting Y - axis is zero.

Solution :-

1) If ( -1, 1 ) is a solution of 6x+5y-k = 0 then it must be satisfying the equation.

Putting x = -1 and y = 1

6x + 5y - k = 0

6(-1) + 5(1) - k = 0

-6 + 5 - k = 0

k = -1

Now, writing any two solutions of

kx+3y-8=0

Put k = -1 in the equation

kx + 3y - 8 = 0

(-1)x + 3y - 8 = 0

3y - x = 8

Now, put any value of 'x' to get 'y'

Let us put x = 1

3y - x = 8

3y - 1 = 8

3y = 9

y = 3

So, one point is ( 1, 3 )

Let us put x = 4

3y - x = 8

3y - 4 = 8

3y = 12

y = 4

So, another point is ( 4, 4 )

( 1, 3 ) and ( 4, 4 ) are two solutions.

2) (2,-1) is a solution of 4x+by+4=0 and ax-2y+3=0

Put x = 2 and y = -1 in given equations

4x + by + 4 = 0

4(2) + b(-1) + 4 = 0

8 - b + 4 = 0

b = 12

ax - 2y + 3 = 0

a(2) - 2(-1) + 3 = 0

2a + 2 + 3 = 0

2a = -5

a = -5/2

So, a + b = 12 - 5/2 = 19/2

3) 3 points which passes through y = x

Put y = 1,2 and 3

then

x = 1,2 and 3

So, three such points are

( 1, 1 ) , ( 2, 2 ) and ( 3, 3 )

4) Line ax+by+c=0 meets Y axis, it means x = 0 for point which meet axis

Put x = 0 in equation

ax + by + c = 0

a(0) + by + c = 0

by + c = 0

y = -c/b

So, point is ( 0, -c/b )

5) Line ax+by+c=0 meets X axis, it means y = 0 for point which meet axis

Put y = 0 in equation,

ax + by + c = 0

ax + b(0) + c = 0

ax + c = 0

x = -c/a

So, point is ( -c/a, 0 )

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