Math, asked by nitafera093, 3 months ago

Answer the following in brief. (3 marks each)
[06]
Q. 11 A5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall
at point 4 m high. If the foot of the ladder is moved 1.6 towards the wall, then find the
distance by which the top of the ladder would slide upwards on the wall.​

Answers

Answered by rashmikerketta1981
1

Step-by-step explanation:

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Answered by Anonymous
0

Question :

5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall

at point 4 m high. If the foot of the ladder is moved 1.6 towards the wall, then find the

distance by which the top of the ladder would slide upwards on the wall.

Answer :

In figure ∆DLW and ∆ERW is a wall DL and RE are two positions of ladder of length 5m .

[ refer the attachment ]

In right angled ∆LWD ,

DW² + LW² = DL² [ By Pythagoras ]

DW² = DL² - LW²

DW² = 5² - 4²

25 - 16 = 9

DW = 9

NOW ,

RW = DW - DR

3 - 1.6 = 1.4 m

In right angled RWE ,

EW² + RW² = RE² [ By Pythagoras ]

EW² = RE² - RW²

5² - 1.4² = 25 - 1.96

23.04

EW = √23.04 = 4.8m

Therefore ,

The distance by the ladder shifted upward =

EL = EW - LW = 4.8m - 4m = 0.8m

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