Answer the following in brief. (3 marks each)
[06]
Q. 11 A5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall
at point 4 m high. If the foot of the ladder is moved 1.6 towards the wall, then find the
distance by which the top of the ladder would slide upwards on the wall.
Answers
Step-by-step explanation:
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Question :
➙ 5 m long ladder is placed leaning towards a vertical wall such that it reaches the wall
at point 4 m high. If the foot of the ladder is moved 1.6 towards the wall, then find the
distance by which the top of the ladder would slide upwards on the wall.
Answer :
➙ In figure ∆DLW and ∆ERW is a wall DL and RE are two positions of ladder of length 5m .
[ refer the attachment ]
In right angled ∆LWD ,
᠉ DW² + LW² = DL² [ By Pythagoras ]
᠉ DW² = DL² - LW²
᠉ DW² = 5² - 4²
᠉ 25 - 16 = 9
᠉ DW = 9
NOW ,
RW = DW - DR
᠉ 3 - 1.6 = 1.4 m
In right angled ∆RWE ,
᠉ EW² + RW² = RE² [ By Pythagoras ]
᠉ EW² = RE² - RW²
᠉ 5² - 1.4² = 25 - 1.96
᠉ 23.04
᠉ EW = √23.04 = 4.8m
Therefore ,
The distance by the ladder shifted upward =
᠉ EL = EW - LW = 4.8m - 4m = 0.8m
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