answer the following question 1) How much heat energy bis necessary to raise the temperatures fo 5 kg of water from 20°c to 100° c?
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Quantity of heat required to raise 5 kg of water from 20 0C to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.) For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.
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