Question

answer the following question 11

Answer 1

see,

given mass of Aluminum is 54 kg

And molecular weight of Aluminum is 27

no of moles = weight/ molecular weight

= 54 / 27

= 2

Hence we have 2 moles of Aluminum from 54 kg.

As per reaction 2 moles of Aluminum gives 2 moles of Iron.

so for 2 moles of iron,

2 moles= weight/ molecular weight of iron

2 = w / 56

w = 56×2

= 112

Hence the weight of required iron is 112 kg.