Question

answer the following question​

Answer 1

Step-by-step explanation:

$i \: use \: al pha \: instead \: of \: theta \\ \sin3 \alpha - \sin\alpha = \sin5 \alpha \\ \sin3 \alpha = \sin6\alpha \\ \ \frac{ \sin }{sin} = \frac{6 \alpha }{3 \alpha } \\ 1 = 2 \alpha \\ \alpha = \frac{1}{2} \\ \\ \\ theta \: is \: \frac{1}{2}$

Answer 2

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