Math, asked by chaviLOVER, 9 months ago

Answer the following question ​

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Answers

Answered by SwaggerGabru
1

Answer:

HOPE THE ATTACHMENT HELPS YOU

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Answered by saivivek16
0

Step-by-step explanation:

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 \text { This is Sweety Adihya }

cos(³/²π+x)cos(2π+x)[ cot(³/2π+x)+ cot(2π+x)]

= sinx × cosx[ tanx+cotx]

= sinx × cosx [ sin²x+cos²x/ sinx*cosx]

=1

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@ Sweety Adihya

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