Question

answer the following question ​

Answer 1

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c.p of 1st= x/7

c.p of 2nd =x/9

total cost price= x/7+x/9

=9x+7x÷ 63

=16x/63

he sold mixed a lot at 8 for a rupees

S.P =12x/8=x/4

hence C.P >S.p

he has loss = C.p - S.p

=16x/63-x/4

(after solve this we get)

=x/63×4

loss%=loss/c.p × 100 ------eq.1

(after the value put in the eq we get)

=25/16

hence loss %= 25/16

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