answer the following question
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let the fixed charge be x and additional charge y
saritha,
x+4y=27-----(1)
Susy,
x+2y=21------(2)
solve (1) and (2) by elimination method
we get , y=3 and x=15
MARK MY ANSWER AS BR
saritha,
x+4y=27-----(1)
Susy,
x+2y=21------(2)
solve (1) and (2) by elimination method
we get , y=3 and x=15
MARK MY ANSWER AS BR
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