Answer the following question
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triangle ABC is congruent to triangle ADC. Since ABCD is a rectangle, it is also a parallelogram. Since ABCD is a parallelogram, segment AB ≅ segment DC because opposite sides of a parallelogram are congruent.
so thus ABC≅ADC
THEY HAVE A COMMON POINT AC
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In ΔABC and ΔADC,
AB=DC
AC=AC [common]
BC=AD
Therefore, ΔABC≅ΔADC [By the S.S.S congruence rule]
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