Question

Answer the following question .​

Answer 1

Answer:

Step-by-step explanation:

Q7

Ans- let the one angle is x

then another one is 2x-30

so it is a parallelogram

then,

x+2x-30=180

3x=210

x=70

and another one is 110

Q8

Ans- Given

∠BOC=44

SOLUTION

∠AOB+∠BOC=180

∠AOB+44=180

∠AOB=180-44

∠AOB=136

OA=OB {Diagnols of rectangle bisect each other}

∠OAB=∠OBA {Angles corresponding to equal sides are equal}

Let ∠OAB=∠OBA=x

In Δ AOB

∠OAB+∠OBA+∠AOB=180   {Angle Sum Property Of a Δ}

x+x+136=180

2x+136=180

2x=180-136

2x=44

x=44/2

x=22

So ∠OAB=22°

Q9

Ans- ∠PSR=180-128=52

∠RQP=360-230=130

∠PRT=35(Given)

∠QPS=360-(35+52+130)=143 (Since PQRS is a quadrilateral)