Question

answer the following question​

Answer 1

Answer:

(i) object distance u = position of convex lens - position of candle

U = -(50 -12) = -38 cm

image distance v = position of screen -position of convex lens

V-88-50 cm

v- 38 cm

(ii) When the candle is shifted towards the lens at a position of 31.0 cm:

Object distance u--(50-31)

U = -19 cm

(iii) If the candle is further shifted towards the lens, then the nature of the image formed will be virtual, erect and magnified

HOPE IT HELPS U☺

Q.4 answer is in attachment

Answer 2

Answer:

Given:

size of object, o=+7cm

distance of object ,u=−27cm

focal length of concave mirror, f=−18cm

let us take size of image=I

so, mirror formula is

v

1

+

u

1

=

f

1

so, putting values of u and v,

v

1

=

−18

1

−

−27

1

v

1

=

−54

1

v=−54cm

so, image is formed on object side only.

magnification,

m=

u

−v

=

o

I

m=−

−27

−54

=

7

I

I=−14cm

so, image is double in size to that of object.