Question

Answer the following question above

Answer 1

Answer:

F = ma = 6N. m= 2kg

2(a) = - 6

a = -3m/s^2. v = 30m/s

So…….. since t = v/a

t needed to stop the object is ….

30/3 = 10s. From 30 m/s to zero requires 10 seconds. Not using calculus here, since it’s simple. I visualize a triangle with velocity V vertical axis and T is a horizontal axis. The area of the triangle gives distance traveled 10 seconds. or (30m/s)(10s)/2= 300m/2 = 150m

Since the deceleration is a constant, I can expect that after five seconds the object has traveled 150m./2 = 75m.

Answer 2

Answer:

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