answer the following question .....answer it step by step
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In triangle CTE, angleATE is the exterior angle
By remote exterior angle theorem
angle TCE +angleTEC = angleATE
35 + 31 = angleATE
angleATE =66 therefore, x= 66
In triangle BSD,
angleBSD+angleSBD +angle SDB = 180
angleBSD+ 30 +36 =180
angleBSD = 114
IN triangle ATS , angle BSD is an exterior angle,
angle BSD = x + y
114 = 66 + y
y = 48
C. 66 and 48
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