Question

Answer the following question based on the given circuit?
(i) The equivalent resistance in the circuit
(ii) The current flowing through in the given circuit
(iii) The potential drop across the 3Ω resistor is
(iv) How many resistors are connected in parallel?
(v) How are the resistors connected?

Answer 1

Solution :

In the above circuit, the 6Ω and 3Ω resistors are in parallel.

Equivalent resistance between them >

>> 6×3/(6+3)

>> 18/9

>> 2Ω .

This is in series with the 4Ω resistor.

Equivalent resistance in the circuit becomes 6Ω .

Now , V = 3V

V = IR

> 3 = 6 I

> I = 3/6 = 0.5 A

Potential drop across the 3 ohm resistor = R_resistor × I (ohm's law)

> 1.5 V

Only two resistors are connected in parallel.

The resistors are connected in parallel and series.

______________________________________

Answer 2

Given :-

Potential difference = 3 V

R1 = 6 Ω

R2 = 3 Ω

R3 = 4 Ω

To Find :-

((i) The equivalent resistance in the circuit

(ii) The current flowing through in the given circuit

(iii) The potential drop across the 3Ω resistor is

(iv) How many resistors are connected in parallel?

(v) How are the resistors connected?

Solution :-

(i)The equivalent resistance in the circuit

1/Rn = 1/R1 + 1/R2

1/Rn = 1/6 + 1/3

1/Rn = 1 + 2/3

1/Rn = 3/3

1/Rn = 1 Ω

Equivalent resistance = (R1 + R2) + R3

Equivalent resistance = 1 + 4

Equivalent resistance = 5 Ω

(ii)  The current flowing through in the given circuit

V = IR

I = V/R

I = 3/5

I = 0.6 A

(iii) The potential drop across the 3Ω resistor is

Potential drop = 3 × 0.6

Potential drop = 1.8 V

(iv) How many resistors are connected in parallel?

Two resistor are connected in parallel

(v) How are the resistors connected?

Two resistor are connected in parallel and one in series