Question

answer the following question..... fast... with steps

Answer 1

$\huge\mathcal{Answer \ :-}$
$<b><i>$
Let the cost of one table and one chair be Rs.x and Rs.y respectively.

A/q

x = 6y - 100

On further solving, we get

x - 6y = -100 _______(1)

Also,

x + 4y = 1400 ________(2)

Subtract (1) and (2), we get

-6y - 4y = -100 - 1400

-10y = -1500

y = 150

Put this in (1), we get

x - 6(150) = -100

x - 900 = -100

x = -100 + 900

x = 800

$\mathsf\red{Cost \ of \ a \ chair \ = \ Rs.150}$

Therefore, Option B. is correct

$\huge\mathbb{Hope \ this \ helps.}$

Answer 2

Hey !!


Let Cost of chair be X .


Cost of table = (6X - 100 ) .



According to the question,



Cost of one table + Cost of 4 chairs = 1400.



6X - 100 + 4 ( X ) = 1400



6X - 100 + 4X = 1400



10X = 1500


X = 150.





Cost of a chair = X = 150.