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Answer:
given that
length of cuboid =5cm
breadth of cuboid =3.5cm
height of cuboid =1.4cm
surface area of cuboid is = 2(lb+bh+hl)
=2(5×3.5+3.5×1.4+1.4×5)
=2(17.5+4.90+7)
=2(29.40)
=58.80cm²
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