Question

answer the following question given below

Answer 1

Hey mate!!

HAPPY RAKSHA BANDHAN!!

Here's your answer!!

$x + \frac{1}{x} = 7 \\ \\ {(x + \frac{1}{x}) }^{2} = {7}^{2} \\ \\ = > {x}^{2} + { \frac{1}{x} }^{2} + 2 x \times \frac{1}{x} = 49 \\ \\ = > {x}^{2} + { \frac{1}{x} }^{2} = 47 \\ \\ \\ \\ = > { (x + \frac{1}{x}) }^{3} = {7}^{3} \\ \\ = > {x}^{3} + { \frac{1}{x} }^{3}+ 3(x + \frac{1}{x} ) = {7}^{3} \\ \\ = > {x}^{3} + { \frac{1}{x} }^{3} + 3(7) = 343 \\ \\ = > {x}^{3} + { \frac{1}{x} }^{3} = 343 - 21 \\ \\ = > {x}^{3} + { \frac{1}{x} }^{3} = 322 \\ \\ \\ \\ { ({x}^{2} + { \frac{1}{x} }^{2} )}^{2} = {47}^{2} \\ \\ = > {x}^{4} + { \frac{1}{x} }^{4} + 2 = 2209 \\ \\ = > {x}^{4} + { \frac{1}{x} }^{4} = 2209 - 2 \\ \\ = > {x}^{4} + { \frac{1}{x} }^{4} = 2207$


Hope it helps!!!