Question

answer the following Question in marathi​

Answer 1

Answer:

answer ok byeeeeeeeeee

Explanation:

answer ok byeeeeeeeeeeeeee

Answer 2

Answer:

$\large\underline{\sf{Solution-}}$

Given that,

$\sf \: 3f(x) + 2f\bigg(\dfrac{1}{x} \bigg) = \dfrac{1}{x} - 5 - - - (1)$

Replace x by $\dfrac{1}{x}$, in equation (1), we get

$\sf \: 3f\bigg(\dfrac{1}{x} \bigg) + 2f(x)= x - 5$

can be rewritten as

$\sf \: 2f(x) + 3f\bigg(\dfrac{1}{x} \bigg) = x - 5 - - - (2)$

On multiply equation (1) by 3 and (2) by 2, we get

$\sf \: 9f(x) + 6f\bigg(\dfrac{1}{x} \bigg) = \dfrac{3}{x} - 15 - - - (3)$

and

$\sf \: 4f(x) + 6f\bigg(\dfrac{1}{x} \bigg) = 2x - 10 - - - (4)$

On Subtracting equation (4) from (3), we get

$\sf \: 5f(x) = \frac{3}{x} - 2x - 5$

On substituting x = 2, we get

$\sf \: 5f(2) = \frac{3}{2} - 4 - 5$

$\sf \: 5f(2) = \frac{3}{2} - 9$

$\sf \: 5f(2) = \frac{3 - 18}{2}$

$\sf \: 5f(2) = \frac{- 15}{2}$

$\sf \: \bf\implies \:f(2) \: = \: - \: \frac{3}{2}$