Question

answer the following question in physics

Answer 1

Ok so lets begin✔
SO GIVEN: mass of body = 10 kg
Initial velocity (u)=5m/s
Final velocity (v)=3m/s
So we beed to find: Work done on the body to bring its velocity from 5 to 3 m/s


So as formula to calculate Work done=F.S
(force × displacement)
But tbis formula cant help us .... therefire we need to use the work energy theorem- This theorem states that the work done on a body is equal to the change in itskinetic energy....so


Work done
$= \frac{1}{2} {mv}^{2} - \frac{1}{2} {mu}^{2}$
$= \frac{1}{2} \times 10 \times {3}^{2} - \frac{1}{2} \times 10 \times {5}^{2}$

$= 45 - 125$
$= - 80joule$

Answer 2

this will help you in solving it