Answer the following question please! Quick!
I would be extremely grateful!
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Kimmus:
Do u need its calculation?
Or just answer?
Calculation
Just answer is of no use to me..If u could help me..Thanks
Can someone answer this too - http://brainly.in/question/357261
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Answers
Answered by
5
⇒ tan26° + tan19° / x(1-tan26°tan19°) = cos60°
⇒ tan(26°+19°) = x × 1/2
= tan45° = x/2
⇒x = 2
I didn't understand
(1-tan26°tan19°) = 1..How ?
I dont know much about this topic..That's why
Sorrry
I couldn't solve this easy problem ?!
I saw :P
Answered by
3
(Tan 26 + Tan 19) / x (1 - tan 26 × tan 19 ) = Cos 60
Tan 26 + Tan 19 = Cos 60 · x (Tan 26 + Tan 19 )
Tan 26 + Tan 19
-------------------------- = x · Cos 60 ------------------------------(1)
1 - (tan 26 × tan 19 )
---------------------------------------------
---------------------------------------------------------------------------
we know,
Tan(A+B) = ( TanA + TanB ) ÷ (1- TanA·TanB )
∴ Tan 26 + Tan 19
-------------------------- = Tan ( 26 + 19 )
1 - (tan 26 × tan 19 )
= Tan 45
= 1//
------------------------------------------------------
--------------------------------------------------------------------------------------
Substituting it in (1)
1 = x · Cos 60
1 = x · 1/2
x = 2 //
Value of X = 2
Tan 26 + Tan 19 = Cos 60 · x (Tan 26 + Tan 19 )
Tan 26 + Tan 19
-------------------------- = x · Cos 60 ------------------------------(1)
1 - (tan 26 × tan 19 )
---------------------------------------------
---------------------------------------------------------------------------
we know,
Tan(A+B) = ( TanA + TanB ) ÷ (1- TanA·TanB )
∴ Tan 26 + Tan 19
-------------------------- = Tan ( 26 + 19 )
1 - (tan 26 × tan 19 )
= Tan 45
= 1//
------------------------------------------------------
--------------------------------------------------------------------------------------
Substituting it in (1)
1 = x · Cos 60
1 = x · 1/2
x = 2 //
Value of X = 2
Hope it helps ^_^...... Any doubts regarding this question persists, Kindly ask it to me. Thank you (:
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