Physics, asked by abdulwasi0036, 9 months ago

Answer the following question :

^ what is the perpendicular distance between the force and the turning point if a force of 25 N produce a moment a force of 12.5 Nm ?

^ a force of 200 N acts on an area of 0.16 m² . what is the magnitude of pressure in pascal ?

^ what is the magnitude of a force which produces a pressure of 700 pa while acting on a surface of area of cross-section 0.25² ?

^ a force F acts on an area of 600 cm² and produce a pressure of 12500 pa. calculate the magnitude of F ?

Answers

Answered by smartbrainz
7

1.given,

The force is equal to 25 Newton

the moment of force is equal to to 12.5 Newton metre

The perpendicular distance is equal to

\frac{moment of force}{force} = 12.5/25 = 0.5 meter

2. Given,

The force of 200 Newton

the surface area is 0.16 m²

The pressure is the force exerted per unit area.

Pressure= \frac{force}{area}  = \frac{200}{0.16} =

1250Pa

3.given,

the pressure exerted is 700 Pascal

the area of cross section is equal to 0.25 meter square

Force = 700x0.25 = 175N

4.given,

The pressure exerted is 12500 Pa

Area on which pressure is exerted = 600cm2 or 0.06m²

The force= 12500x 0.06 = 750N

Answered by priyambadmohanty1
2

Answer:

Answer the following question :

^ what is the perpendicular distance between the force and the turning point if a force of 25 N produce a moment a force of 12.5 Nm ?

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