Math, asked by nightread, 4 months ago

Answer the following Question with full Explanation :-
The odometer of a car reads 50550.0 km when the clock shows the time 08:00 AM. What is the distance moved by the car, if at 08:50 AM, the odometer reading has changed to 50610.0 km?
Calculate the speed of the car in kmh^{-1} during this time. Express the speed in ms^{-1} also.

Answers

Answered by Sweetoldsoul
3

Answer:

POINTS TO KNOW FOR THIS QUESTION

  • Odometer - An odometer is an instrument used for measuring the distance traveled by a vehicle, such as a bicycle or car.
  • speed in a time period T = distance/ time (T)

SOLUTION

=> at time 08 : 00 AM  the car is at 50550.0 km

So, initial distance = 50550 km

=> at time 08 : 50 AM the car is at 50610.00 km

So, final distance = 50610 km

from 08 : 00 AM to 08 : 50 AM the time that's passed is T = 50 mins.

=> T = 50 mins

(1 min = 1/ 60 hr.. => 50 mins = 50/ 60 hr)

=> T = 5/ 6 hr

In 50 mins, the distance moved by the car = 50610 - 50550

D = 60 km

Speed of the car during this time = distance/ time

= \frac{60}{5/ 6}

= \frac{60 * 6}{5}

= \frac{12 * 6}{1}

= 72 km/ h

Thus, the speed of the car is 72 km/ h during the given time period. (Ans

Converting km/ h to m/ s :-

=> 72 x \frac{5}{18}

=> 4 x 5

=> 20 m/ s

The speed in m/ s is 20 m/ s (Ans

(The meter on the right side is the odometer)

Attachments:
Answered by Aripthajoysce120735
3

Answer:4*5 = 20m/s

Odometer reading at 8 am = 50550km

Odometer reading at 8.50 am = 50610km

Distance travelled = 50610-50550

= 60km

Time= 50min = 5/6hour

Speed = distance/time

=60/5/6 = 60*6/5 = 360/5 = 72km/h

(kmph to mps--)

72 * 1000/3600 = 72*5/18

= 4*5 = 20m/s.

Step-by-step explanation:

HOPE IT HELPS

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