Chemistry, asked by eshu61, 1 year ago

Answer the following questions :-

1) calculate the number of electrons constituting one coulomb of charge?

2) Name a device that helps to maintain a potential difference across a conductor?

3) Explain how a cell maintain an electric current in a circuit?

4) How much energy is given to each coulomb of charge passing through a 6 v battery?

5) The given figure shnoows a bar magnet NS placed on the tableop in north-south direction with its N-pole pointing towards the north. No other magnet or magnonetic material is present in its neighborhood.

a) when will you get neutral points on plotting a magnetic field of the magnet?

b) what is the magnitude of magnetic field at each of the neutral points? give reason.
----------------------------------------------
Warning - don't spam

Thanks!
---------------------------------------------

Answers

Answered by DimpleDoll
101
 \underline\mathfrak{Answer \: the \: following \: question -}

 <i><b>

Ans 1. We know that magnitude of change on an electron,

 \bold{e \: = 1.6 \times {10}^{ - 19} c}

therefore, number of electrons constituting 1 coulomb of charge, n = q/e

 \bold{ = \frac{1 \: c}{1.6 \times {10}^{ - 19} c} \: = 6.25 \times {10}^{18} }

Ans 2. A cell(electrochemical cell) and a battery of cells are the devices commonly used to maintain a potential difference across a conductor.

Ans 3. The chemical action within a cell produced a potential diff. across the terminals of the cell even when no current is being drawn from it. when a conducting circuit is connected across the terminals of a cell, the potential diff. sets the charges in motion in the circuit and constantly an electric current is produced in the circuit. thus, chemical energy stored in the cell is being continuously spent for maintaining current flow in an electric circuit.

Ans 4. As potential difference between the terminals of a battery is 6 V, hence, an energy of 6 J must be given for each coulomb of charge passing through the battery.

Ans 5. (a) We shall get two neutral points, one on either side of the magnet, along its equatorial line.

(b) The magnitude of magnetic field at either neutral points is zero. it is because magnetic field of a magnet, being equal and opposite to magnetic field of the earth at these points, is nullified the by earth's magnetic field.

 \small \red{I \: Hope \: This \: Helps \: You}

#be brainly

brijeshpbhkmgm8: hello
brijeshpbhkmgm8: how are you
brijeshpbhkmgm8: hello dimple doll
brijeshpbhkmgm8: yrr reply to do
Similar questions