Physics, asked by Anonymous, 1 year ago

answer the following questions​

Attachments:

Answers

Answered by ShivamKashyap08
2

\huge{\bold{\underline{\underline{....Answer....}}}}

\huge{\bold{\underline{Given:-}}}

\huge{ \Delta l = 1mm = 0.1 cm}

\large{ \Delta r = 0.1mm = 0.01 cm}

\huge{\bold{\underline{Explanation:-}}}

\large{\bold{Volume = \pi \: r^2 l}}

Applying error equation to volume.

\large{ \frac{ \Delta V}{V} = 2 \times  \frac{ \Delta r }{r} + \frac{ \Delta l}{l}}

Substituting the values.

\large{ \frac{ \Delta V}{V} = 2 \times  \frac{ 0.01 }{1} + \frac{0.1}{100}}

\large{ \frac{ \Delta V}{V} =   \frac{2}{100} + \frac{0.1}{100}}

\large{ \frac{ \Delta V}{V} = \frac{2.1}{100}}

\large{ Percentage \: error = \frac{2.1}{100} \times 100 }

\large{ Percentage \: error = 2.1 \%}

So, percentage error is 2.1 %.

Attachments:
Similar questions