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Answers
Answer:
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Question:
A woman is now 30 years older than her son. 15 years ago, she was twice as old as her son. What are the present ages of woman and her son?
Answer:
The present age of the woman is 75 years.
And the present age of her son is 45 years.
Step-by-step-explanation:
Let the present age of woman be x years.
And the present age of her son be y years.
From the first condition,
x = y + 30 - - ( 1 )
From the second condition,
( x - 15 ) = 2 ( y - 15 )
⇒ x - 15 = 2y - 30
⇒ x - 2y = - 30 + 15
⇒ x - 2y = - 15
⇒ ( y + 30 ) - 2y = -15 - - [ From ( 1 ) ]
⇒ y + 30 - 2y = - 15
⇒ - y = - 15 - 30
⇒ - y = - 45
∴ y = 45
By substituting y = 45 in equation ( 1 ), we get,
x = y + 30
⇒ x = 45 + 30
⇒ x = 75
∴ The present age of the woman is 75 years.
And the present age of her son is 45 years.