answer the following questions 21
q (1 to 4)
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as we know that chlorine atom first contain 2,8,7 I.e. it is deficient of one electron and as it gains one electron it completes it octet and becomes anion as it has gained one electron which is more than chlorine atom
argon being an inert gas has its all shells incomplete thus there is a force of repulsion between nucleus and last electron
because across the period the atomic size decreases thus making hard to extract valence electrons
alkali metals have one valence electron which they lose and undergo oxidation hence they are reducing agent
argon being an inert gas has its all shells incomplete thus there is a force of repulsion between nucleus and last electron
because across the period the atomic size decreases thus making hard to extract valence electrons
alkali metals have one valence electron which they lose and undergo oxidation hence they are reducing agent
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21. i)cl- ion has one electron more than the neutral cl atom .therefore the effective positive charge in the nucleus of cl- ion is less ,so less inward pull is experienced. As a result the size expands.
ii) argon is an inert gas,so its outermost shell is completely filled .As a result ,electronic repulsion are maximum and the size expands. Thus ,argon atom is bigger than chlorine atom.
iii)across a period the atomic size decreases from left to right due to increase in nuclear charge. Hence,more energy is required to remove the electron (s)
iv) the metallic character of alkali metals is maximum. so,they easily lose electron(s) to complete their octet. thus they are good reducing agents because greater the tendency to lose electron(s) ,stronger is the reducing agent.
Hope this helps!!!
ii) argon is an inert gas,so its outermost shell is completely filled .As a result ,electronic repulsion are maximum and the size expands. Thus ,argon atom is bigger than chlorine atom.
iii)across a period the atomic size decreases from left to right due to increase in nuclear charge. Hence,more energy is required to remove the electron (s)
iv) the metallic character of alkali metals is maximum. so,they easily lose electron(s) to complete their octet. thus they are good reducing agents because greater the tendency to lose electron(s) ,stronger is the reducing agent.
Hope this helps!!!
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