Question

ANSWER : the following questions ​

Answer 1

Explanation:

a) (i) uniform acceleration

(ii) constant

(iii) uniform retardation

b) acceleration in the first two hours

• u=40km/h , v=0km/h , t=2h
• a=v-u/t
• a=40-0/2
• a=20 km/h²

acceleration in the next two hours

• v=40km/h , u=40km/h , t=2h
• a=v-u/t
• a=40-40/2
• a=0/2
• a=0 km/h

acceleration in the next two hours

• u=40 km/h , v=0 km/h , t=2 h
• a=v-u/t
• a=0-40/2
• a= -20 km/h

c) total distance travelled by the car =area of ∆ab2+area of trapezium 2bde

total distance = 1/2×b×h + 1/2×sum of || sides × h

=1/2×2×40 + 1/2×(6+4)×40

=40 +10×20

=40+200

=240 km

d) average speed=total distance / total time

=40/8

=10/2

=5 km/h