answer the following questions
Attachments:
Answers
Answered by
1
Let the number be 10x+y, where digit at 10s place is x and digit at unit place is y.
Given,
x + y = 8 -----(1)
(10x+y) + 8 = 10y+x
9x - 9y = -8 -----(2)
(1) × 9 + (2) gives,
18x = 64
x = 64/18 which is not an integer.
So such a number doesn't exist
Given,
x + y = 8 -----(1)
(10x+y) + 8 = 10y+x
9x - 9y = -8 -----(2)
(1) × 9 + (2) gives,
18x = 64
x = 64/18 which is not an integer.
So such a number doesn't exist
Similar questions