Question

answer the following questions ​

Answer 1

Answer:

Total dices=2

Total sample space in two dices, n(S)=6×6=36

Let E = Event of getting the numbers whose difference is 2

= {(1,3),(2,4),(3,5),(4,6),(3,1),(4,2),(5,3),(6,4)}

$n(e) = 8 \\ \\ p(e) = \frac{n(e)}{n(s)} \\ \\ = \frac{ \cancel8 \: ^{2} }{ { \cancel{36}} \: ^{9} } \\ \\ = \frac{2}{9}$

Hope it helps you from my side :)

Answer 2

Answer:

Total dices=2

Total sample space in two dices, n(S)=6×6=36

Let E = Event of getting the numbers whose difference is 2

= {(1,3),(2,4),(3,5),(4,6),(3,1),(4,2),(5,3),(6,4)}.

n(e) = 8.

p(e) = n(e)/n(s).

= 8²/36^9 = 2/9.