Question

answer the following questions

Answer 1

so 1st number=x
2nd number =y
3rd number=z
so , prime factors are given
x=2×2×3×3×3×5×5×5×5×5
y=2×2×2×3×3×5×5×7
z=2×2×2×2×3×3×3×3×5×7×7
h.c.f=common factors
h.c.f=2×2×3×3×5
h.c.f=4×9×5
h.c.f=36×5
h.c.f=180........
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