Answer the following questions. (Any 2) [6] For a concave mirror with focal length 15cm,object distance is 10 cm and the height of the object is 2 cm. Find the position, size and nature of the image.
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1
Answer:Size = 4 cm
Explanation:Height of object = 2cm
Object distance = 15cm
Focal length = 10cm
1/f = 1/v +1/u
-1/10 = -1/15 +1/v
1/v = -3 +2 /30
v = -30 cm
Height of image/Height of object = -v /u
Height of image / 2 = 30/-15
Height of image = - 4cm
Nature - Real and inverted
Position - 30 cm from concave mirror
Size = 4 cm
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Explanation:
We know that,
v
1
+
u
1
=
f
1
u = -15 cm
Focal length = -10 cm
∴
v
1
=
−10
1
−
(−15)
1
⇒
v
1
=
−10
1
+
15
1
=
30
−3+2
=−
30
1
⇒v=−30cm
Magnification (m)=
u
v
=
Object height
Image height
m=−
u
v
=+
−15
30
=−2
Also, Image height=−2×6=−12 cm
Therefore, a real, inverted and enlarged image of the object is formed beyond the centre of curvature.
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