Question

answer the following questions any two

Answer 1

$\huge\red{{\mathfrak{Hey\: dear!}}}$

$\huge\mathcal\red{Here \:is the\: answer...}$

$\huge\textt{Question 1 :-}$

Find the compound interest if Rs. 1000 is invested for 2 years at the rate of 10 % p.a.

$\huge\textt{Solution :}$

Principal(P) = Rs. 1000

Time(n)= 2 years

Rate (r)= 10%

Therefore,

Amount = $P{(1 + \frac{r}{100})^{ n} }$

$= 1000{(1 + \frac{10}{100})^{2} }$

$= 1000 \times ( \frac{11}{10})^{2} \\ \\ = 1000 \times \frac{121}{100} \\ \\ = Rs. 1210$

Therefore,

Compound Interest = Amount -Principal

= Rs. (1210-1000)

= Rs. 210

$\huge\textt{Question 2 :-}$

If P= Rs. 2000, r= 5%, n= 2 years, find the simple interest.

$\huge\textt{Solution :}$

Principal(P)= Rs. 2000

rate(r) = 5 %

time(t) = 2 years

Therefore,

Simple Interest= $\frac{P\times r \times t}{100}$

$= \frac{2000 \times 5 \times 2}{100} \\ \\ =Rs. 200$

$\huge\textt{Question 3 :-}$

If the principal Rs. 10000 amounts to Rs. 13924 in two years calculate the compound interest.

$\huge\textt{Solution :}$

Principal = Rs. 10000

Amount = Rs. 13294

Therefore,

Compound Interest = Amount -Principal

= Rs. ( 13294- 10000)

= Rs. 3294.

I hope it helps you....