Question

answer the following questions as directed
Any 1
no.33​

Answer 1

Step-by-step explanation:

I hope this answer is helpful for you

Answer 2

Answer:

f(x)=x³-23x²+142x-120

We know that if the sum of the coefficients is equal to 0 then (x-1) is one of the factors of given polynomial.

f(1)=1³-23×1²+142(1)-120

= 1-23+142-120

=0

therefore (x-1) is a factor of x³-23x²+142x-120.

deviding x³-23x²+142x-120 by (x-1) we get  (x²-22x+120)

finding factors of  (x²-22x+120)

x²-22x+120

= x²-10x-12x+120

=x(x-10)-12(x-10)

=(x-12)(x-10)

factors of  x²-22x+120 are (x-12)(x-10)

hence factors of x³-23x²+142x-120 are (x-1) (x-12)(x-10)

refer→→ https://brainly.in/question/1227722