Question

Answer the following questions before 4'o clock​

Answer 1

Please mark brainliest.

Answer 2

Solution 1:

∠ACD is exterior angle of △ABC

∠A = ∠B

∠ACD = 130°

We know that exterior angle of triangle is equal to the sum of opposite two angles. Hence,

∠A + ∠B = ∠ACD

2∠A = 130°

∠A 130/2 = 65°

∠A = ∠B= 65°

Solution 2:

Line AC is intersecting line BD at C which forms a linear pair

i.e. ∠ACD + ∠ACB = 180°

∠ACB = 180 - 130 = 50° (as ∠ACD = 130°)

∠ACB is ∠C

Sum of angles of triangle is 180°

∠A + ∠B + ∠C = 180°

2∠A = 180 - 50 = 130°

∠A = 130/2 = 65°

So, ∠A = ∠B = 65°