Answer the following questions briefly and to the point:
(1) A student measures the length of a rod with an ordinary centimeter scale and records the result as
15cm What would you suggest about the result by keeping in mind, the importance of the least count of
the measuring instrument in the experimental Physics.
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The measured distance by the student is 3.50 cm which means the least count of the measurement done is 0.01 cm.
A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mm
similarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mm
A meter scale has a least count of 1 mm.
And the least count of a vernier caliper which has 10 divisions in 1 cm on main scale and 10 divisions in vernier scale match with 9 division in main scale can be given as
1 cm/(10*10) = 0.01 cm
Thus the student must have used the vernier caliper for the measurement.
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A screw gauge having 100 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(100) i.e. 0.01 mm
similarly screw gauge having 50 divisions on a circular scale with a pitch of 1 mm will have a least count of (1 mm)/(50) i.e. 0.5 mm
A meter scale has a least count of 1 mm.
And the least count of a vernier caliper which has 10 divisions in 1 cm on main scale and 10 divisions in vernier scale match with 9 division in main scale can be given as
1 cm/(10*10) = 0.01 cm
Thus the student must have used the vernier caliper for the measurement.
Please mark as the Brainly answer for the answer
And don’t forget to thank me for the answer
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