Question

Answer the following questions, considering ABC as an isosceles triangle.
i) The base BC is two third of each of the other two equal sides. If the perimeter of the triangle is 560 m, find each side.
ii) If the length of the equal sides AC and AB is equal to three fourth of the base BC, keeping the perimeter constant what will be the sides?
iii) If each base angle is 1/2 the vertical angle, then check whether ABC is a right triangle.

Answer 1

Answer:

Given AB=AC

P=a+b+c=24

x+x+

3

2x

=24

3



8x

=



24

3

x=9

∴9,9,



3

2

×



9

3

⇒9,9,6 are sides.