Question

Answer the following questions using the given chemical equation below. Useanother sheet of paper for your solution and answer.KNO3----> KNO2 + O21. Balance the given chemical equation.2. Write the rate of expression of the chemical equation.3. How fast is KNO3 decreasing when oxygen (O2) is increasing at 1.75 x 10^-3 mol/L.s?4. How fast is oxygen (O2) is increasing when KNO2 is increasing at 2.25 x10-4mol/L.s?​

Answer 1

KNO3 = KNO2 + O2

You know that the coefficient for KNO3 must equal the coefficient for KNO2. The product of the coefficient for KNO3 and the subscript for O, which is 3, must be even. So knowing the above, 2KNO3 = 2KNO2 + O2 is the answer. To check: 2x3=6O on left and 2x2=4 + 1x2=2 4+2=6O on right.

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