Question

Answer the follwing proof​

Answer 1

today's ssc board paper right

first in triangle CDA and triangleCDB apply the theorem of ratio of area of two triangle

then your answer will come as

AD/DE= A(triangleCDA)/A(triangle CDB).........1

next apply the theorem of ratio AF square of similar triangle in triangle in CDA and CDB and answer will be

AE^2/EB^2=A(triangleCDA)/A(triangle CDB).........2

from 1and 2

AD/DE=AE^2/EB^2