answer the follwing using identity 1 (203)squar
Answers
Answered by
3
(203)^2
= (200 + 3)^2
= (200)^2 + (3)^2 + 2(200)(3)
= 40000 + 9 + 1200
= 41209
Using identity [ (a+b) ^2 = a^2 + b^2 + 2ab]
= (200 + 3)^2
= (200)^2 + (3)^2 + 2(200)(3)
= 40000 + 9 + 1200
= 41209
Using identity [ (a+b) ^2 = a^2 + b^2 + 2ab]
Answered by
1
203 whole square = (200+3) whole squar
here, we can apply (a+b) whole square property which is = a square + b square + 2ab
so, (200+3) whole square = 200 square + 3 square + 2(200)(3)
= 40000 + 9 + 1200
=41209
here, we can apply (a+b) whole square property which is = a square + b square + 2ab
so, (200+3) whole square = 200 square + 3 square + 2(200)(3)
= 40000 + 9 + 1200
=41209
Similar questions