Answer the full question marked as 2.
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Answer:
a) OA+OB>AB --- i
b) OB+OC>BC --- ii
c) OA+OC>AC --- iii
now- i+ii+iii=>
(OA+OB)+(OB+OC)+(OA+OC)>
AB+BC+AC
=> (OA+OA)+(OB+OB)+(OC+OC)>
AB+BC+AC
=>2OA+2OB+2OC> AB+BC+AC
=> 2 (OA+OB+OC)> AB+BC+AC
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