Question

Answer the give question ...​

Answer 1

initial velocity of ball u=0

final velocity v=19.6m/s

time taken (t)=6s

acceleration due to gravity=9.8m/s^2

distance =height=?

by using

2as=v^2-u^2

2×9.8×h=(19.6)^2-0

19.6h=(19.6)^2

h=19.6×19.6/19.6

h=19.6 m

Answer 2

Here distance is in the form of height

Speed=distance/time

19.6=d/6

d=19.6×6

=117.6m