Question

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Answer 1

Answer :

• The minimum required force F to start moving B is 1100 N

Solution:

•Mass of block A = 100 kg

•Mass of block B = 200 kg

The coefficient of friction between A and B = 0.2

The coefficient of friction between B and the ground  = 0.3

We need to find the minimum force F required to start moving block B

But inorder to find F first we need to draw all the forces on block B

Pls refer the attachment first for better understanding

From the diagram we can conclude that

$\rightarrow \mathtt{F = f (AB ) + f ( BG ) }....(1)$

________________

$\rightarrow \mathtt{ f (AB ) = \mu \: m_A \: g }$

$\rightarrow \mathtt{ f (AB ) = 0.2 \times 100 \times 10}$

$\rightarrow \mathtt{ \orange{f (AB ) =200 \: N}}....(2)$

_________________

$\rightarrow \mathtt{ f ( BG ) =\mu \: (m_A + m_b) \: g }$

$\rightarrow \mathtt{ f ( BG ) =0.3\: (100 + 200) \times 10}$

$\rightarrow \mathtt{ f ( BG ) =0.3 \times 300 \times 10}$

$\rightarrow \mathtt{ \pink{ f ( BG ) =900 \: N}}...(3)$

________________

Substituting the values of (2 ) and (3) in (1) we get ,

$\rightarrow \mathtt{F = 200+ 900 }$

$\rightarrow \mathtt{ \red{F = 1100 N }}$