Answer the given question.
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Join B and E.
ABED is a cyclic quadrilateral.
ADE = EBC … (1)
(exterior angle of a cyclic quadrilateral = Interior opposite angle)
Similarly, EFCB is a cyclic quadrilateral.
EBC + CFE = 180 … (2)
(opposite angles of a cyclic quadrilateral are supplementary)
From (1) and (2),
ADE + CFE = 180
But these are interior angles made by the transversal DF on the same side of the lines AD and CF. Since, these angles are supplementary, therefore,
AD||CF
Answered by
0
Join B and E
ABED is a cyclic quadrilateral
ADE=EBC-------1
(Exterior angle of a cyclic quadrilateral=interior angle)
EFCB is cyclic quadrilateral
EBC+CFE=180--------2
from 1 and 2
ADE +CFE=180
SO,
AD||CF
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