Question

answer the given question? ​

Answer 1

answer:

Let us first calculate equivalent capacitance between A and B.

Ce=1μF (In series combination)

∴ Charge on the combination,

q=CV=1×60=60μC

As 6μF capacitor is in series with all other capacitors, hence, charge on 6μF capacitance is also 60μC,

∴ Potential difference across 6μF capacitor

V1=qC1=606=10V