Question

answer ..................the molality of 10% NaOH solution is.........

Answer 1

2.77m... it's in the netNumber of moles of NaOH present = Mass / Molar Mass = 10/40 = 0.25 mol of NaOH. Mass of water present in a solution = 100-10 = 90 g water =0.090 kg water. Number of moles of water = 90 /18 = 5 mol of water. Molality = Number of moles of solute / kg of solvent = 0.25/0.090 = 2.77 m Naoh