Question

answer the Q5 please​

Answer 1

Answer:

hey bro

Physics 5 points ? Correct question: shows a part of an electric circuit. The reading of the ammeter is 3.0 A. Find the currents through the 10 ohm and 20 ohm resistors. Solution : let the 10 ohm resistor x R_1 and 20 ohm resistor R_2 let the current in 10 ohm resistor be 11 and current in 20 ohm resistor be in reading of ammeter be 1 1 = 3.0ohm; 11=IR \ 2O/(R \ 1+R \ 2); =30*20/(10+20) = 60/30 =2A current flowing through R_1 is 2 amp 2=1R \ 1/(R \ 1+R \ 2); =3*10/(10+20); =30/30; =1 amp => Current flowing through R_2 is 1 amp

Answer 2

Answer:

By bringing two bars near ordinary ironn