Question

answer the ques........​

Answer 1

Explanation:

ANSWER :

The velocity with which the gun recoil is$\sf - 1 \: m/s^{2}−1m/s$

2

The force exerted on gun man due to recoil of the gun is 1000 N.

GIVEN :

Mass of gun = 3 kg.

Mass of bullet = 30 g.

Time, t = 0.003 sec.

Velocity, v = 100 m/s.

TO CALCULATE :

The velocity with which the gun recoils.

The force exerted by the gun man due to recoil of the gun.

FORMULA :

$\sf Force \: = \: \dfrac {\Delta p}{\Delta t}$Force=

Δt

Δp

SOLUTION :

Net force on gun and bullet, system is zero.

$\hookrightarrow [tex]\sf 3 \: \times \: v \: (30 \times 10^{-3}) \: \times 100 \: = \:$ 0↪3×v(30×10

−3

)×100=0

$\hookrightarrow \sf 3v \: = \: - (30 \: \times \: 10^{-1}$↪3v=−(30×10

−1

$\therefore \boxed{\sf V \: = \: - 1 \: m/s^{2}}∴ </p><p>V=−1m/s$

2

$\bold\red{Force \: = \: \dfrac {\Delta p}{\Delta t}}$Force=

Δt

Δp

$\hookrightarrow↪ \sf \dfrac {m(v \: - \: 0)}{0.003}$

0.003

m(v−0)

$\hookrightarrow↪ \sf \dfrac {3 \: \times \: 1}{0.003}$

0.003

3×1

$\therefore \boxed{\sf F \: = \: 1000 \: N}$∴

F=1000N

Answer 2

Answer:

Explanation:

ANSWER :

The velocity with which the gun recoil is\sf - 1 \: m/s^{2}−1m/s−1m/s

2

−1m/s

2

The force exerted on gun man due to recoil of the gun is 1000 N.

GIVEN :

Mass of gun = 3 kg.

Mass of bullet = 30 g.

Time, t = 0.003 sec.

Velocity, v = 100 m/s.

TO CALCULATE :

The velocity with which the gun recoils.

The force exerted by the gun man due to recoil of the gun.

FORMULA :

\sf Force \: = \: \dfrac {\Delta p}{\Delta t}Force=

Δt

Δp

Force=

Δt

Δp

SOLUTION :

Net force on gun and bullet, system is zero.

\hookrightarrow [tex]\sf 3 \: \times \: v \: (30 \times 10^{-3}) \: \times 100 \: = \:↪[tex]3×v(30×10

−3

)×100= 0↪3×v(30×10

−3

)×100=0

\hookrightarrow \sf 3v \: = \: - (30 \: \times \: 10^{-1}↪3v=−(30×10

−1

↪3v=−(30×10

−1

\therefore \boxed{\sf V \: = \: - 1 \: m/s^{2}}∴ V=−1m/s∴

V=−1m/s

2

∴V=−1m/s

2

\bold\red{Force \: = \: \dfrac {\Delta p}{\Delta t}}Force=

Δt

Δp

Force=

Δt

Δp

\hookrightarrow= \sf \dfrac {m(v \: - \: 0)}{0.003}↪↪

0.003

m(v−0)

0.003

m(v−0)

\hookrightarrow↪ \sf \dfrac {3 \: \times \: 1}{0.003}↪↪

0.003

3×1

0.003

3×1

\therefore \boxed{\sf F \: = \: 1000 \: N}∴

F=1000N

∴

F=1000N

Explanation:

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