Question

answer the question​

Answer 1

Answer: Hi Mayra!

Your answer is as follows:

Given,

∠COY=90°

Thus, ∠COX = 180°-90°=90° (linear pair)

GIven,

∠p:∠q = 2:3

Let the magnitude of the ratio be x

Thus, ∠p = 2x

         ∠q = 3x

∠p +∠q = ∠COX = 90°

→ 2x + 3x = 90°

→ 5x = 90°

→x = 90°/5 = 18°

∴ ∠q = 3x =3 ×18° = 54°

∴∠r = ∠BOX = 180° - ∠q (linear pair)

                    = 180°-54° = 126°

If this answer helped you, please mark me as brainliest

Answer 2

<XOY = 180

<COY = 90

<XOC = <XOY - <COY = 180-90 = 90

P+ Q = 90

P:Q = 2:3

P = 90×2/5. = 36

Q = 90× 3/5 = 54

<AOB= 180

Q+ R= 180

R= 180-Q = 180-54 = 126