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an=a+(n-1)d
a3=a+2d=6
a17=a+16d=34
subtracting the above two equations
14d=28
d=2
therefore
a=2
a12=a+(12-1)d
=2+11*2
=24
Hope this helps.
mayra31:
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Answer:
a3= a+ 2d____(1)
a17=a+16d____(2)
by solving 1 and 2 we get the value 'a' and 'd' as 2
a=2,d=2
there fore putting the values and solving a12
we get the 12th term
which is a12= 24
I hope you understood
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